document.write( "Question 1200438: Harry invested $4,000.00 in two investments: one investment was a CD that paid 3.4% annual
\n" );
document.write( "interest, and the other investment was a bond that paid 2.5% annual interest. If he received a check in
\n" );
document.write( "the mail at the end of the year for $114.40 for both investments, how much did he invest in the CD? \n" );
document.write( "
Algebra.Com's Answer #834575 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The response from the other tutor sets the problem up using the standard formal algebraic method. \n" ); document.write( "If formal algebra is not required, here is a way to solve any 2-part mixture problem like this with less work. \n" ); document.write( "A return of $114.40 on an investment of $4000 is an interest rate of 114.40/4000 = 0.0286 or 2.86%. \n" ); document.write( "Compare that to the two separate interest rates of 2.50% and 3.40% and observe/calculate that 2.86% is 0.36/0.90 = 2/5 of the way from 2.5% to 3.4%. That means 2/5 of the total was invested at the higher rate. \n" ); document.write( "ANSWERS: 2/5 of $4000, or $1600, was invested at 3.4%; the other $2400 at 2.5%. \n" ); document.write( "CHECK: .034($1600)+.025($2400) = $54.40+$60.00 = $144.40 \n" ); document.write( " \n" ); document.write( " |