document.write( "Question 1200392: You want to obtain a sample to estimate a population proportion. At this point in time, you have no reasonable preliminary estimation for the population proportion. You would like to be 98% confident that you estimate is within 1.5% of the true population proportion. How large of a sample size is required? \n" ); document.write( "
Algebra.Com's Answer #834573 by Theo(13342)\"\" \"About 
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at 98% two tailed confidence interval, the critical z-score is plus or minus 2.326347877.
\n" ); document.write( "the standard error is equal to the standard deviation divided by the square root of the sample size.
\n" ); document.write( "you want the margin of error to be maximum of .015.
\n" ); document.write( "your critical z-score formula becomes z = .015 / s which becomes 2.326347877 = .015 / s, where s is the standard error.
\n" ); document.write( "solve for s to get s = .015 / 2.326347877 = .0064478749.
\n" ); document.write( "the formula for s is s = sqrt(p * q / n)
\n" ); document.write( "s is maximum when p = .5.
\n" ); document.write( "you get s = sqrt(.5*.5/n)
\n" ); document.write( "since s = .0064478749, then you get .0064478749 = sqrt(.25/n) = sqrt(.25) / sqrt(n).
\n" ); document.write( "solve for sqrt(n) to get sqrt(n) = sqrt(.25) / .0064478749 = 77.54492924.
\n" ); document.write( "solve for n to get n = that squared = 6013.21605.
\n" ); document.write( "when n = that, maximum s will be sqrt(.25/6013.21605) = .0064478749.
\n" ); document.write( "this indicates that the sample size shuld be greater than 6013.21605.
\n" ); document.write( "nearest integer greater than 6013.21605 = 6014.
\n" ); document.write( "regardless of what the mean proportin is, the margin of error should be less tha .015 when the sample size is 6014 or more.
\n" ); document.write( "to test this out, we'll look at some possible mean proportiong to see if this is true.
\n" ); document.write( "at p = .5, you get s = sqrt(.5*.5/6014) = .0064474546.
\n" ); document.write( "you get 2.326347877 = (x-m) / .0064474546
\n" ); document.write( "solve for (x-m) to get (x-m) = 2.326347877 * .0064474546 = .014999 which is less than .015.
\n" ); document.write( "when p = .9, you get s = sqrt(.9*.1)/6014) = .0038604720.
\n" ); document.write( "your z-score formule becomes 2.326347877 = (x-m) / .008604720.
\n" ); document.write( "solve for (x-m) to get (x-m) = .0089994134 which is less than .015.
\n" ); document.write( "you should be guaranteed that the magin of error will be less than .015 when the sample size is 6014 or greater.
\n" ); document.write( "i had to do this many times to make sure i did it correctly.
\n" ); document.write( "i'm reasonably certain that i finally got it right.
\n" ); document.write( "my best guess is a sample size of 6014 or greater will satisfy the requirement that the margin of error is less than .015 regardless of the value of p.\r
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