document.write( "Question 1200431: A boy cycles 8km on a bearing of 060°.
\n" ); document.write( "How far is the boy North of his starting
\n" ); document.write( "point? Give your answer to 2 s.f.
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Algebra.Com's Answer #834556 by math_tutor2020(3816)\"\" \"About 
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\n" ); document.write( "Start facing directly north.
\n" ); document.write( "Then turn 60 degrees toward the east (i.e. to the right).
\n" ); document.write( "This will align you with the bearing 060°
\n" ); document.write( "This is in the northeast quadrant.\r
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\n" ); document.write( "\n" ); document.write( "Compass Rose:
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\n" ); document.write( "Image courtesy of Wikipedia.
\n" ); document.write( "https://en.wikipedia.org/wiki/File:Compass_rose.png\r
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\n" ); document.write( "\n" ); document.write( "This is what your rough sketch of the diagram should look like
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\n" ); document.write( "The boy starts at point P and moves to point Q.
\n" ); document.write( "Note that 60+30 = 90.\r
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\n" ); document.write( "\n" ); document.write( "Let's erase the vertical line and erase the \"60 degree\" label.
\n" ); document.write( "I'll add in a vertical line from Q to drop down to the horizontal line.
\n" ); document.write( "It has length x to represent how far north Q is compared to P.
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\n" ); document.write( "The goal is to have a right triangle, so we can use a trig ratio to determine x.\r
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\n" ); document.write( "\n" ); document.write( "sin(angle) = opposite/hypotenuse
\n" ); document.write( "sin(30) = x/8
\n" ); document.write( "x = 8*sin(30)
\n" ); document.write( "x = 8*0.5
\n" ); document.write( "x = 4
\n" ); document.write( "This value is exact.
\n" ); document.write( "Make sure your calculator is in degree mode.\r
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\n" ); document.write( "\n" ); document.write( "Answer: 4 km
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