document.write( "Question 1199897: 2.A doctor claims that about 30 percent of all persons exposed to a certain amount of radiation will feel any ill effects. Among 19 randomly selected samples who were exposed to radiation, only 1 felt any ill effects.
\n" ); document.write( "A.Construct the 95% confidence interval for the population proportion?
\n" ); document.write( "B.Test whether the proportion of population who are exposed to radiation fell any ill effect is less than doctor’s claim α = .05 level of significance?
\n" ); document.write( " test the null hypothesis θ = 0.30 against the alternative hypothesis θ < 0.30 at the α = .05 significance level \n" ); document.write( "

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claim is population p = 30%
\n" ); document.write( "sample size is 19.
\n" ); document.write( "sample p = 1/19 = .0526 * 100 = 5.26%
\n" ); document.write( "test is whether actual percent is less than 30.
\n" ); document.write( "standard error equals (30 * 70 / 19) = 10.5
\n" ); document.write( "z = (5.26 - 30) / 10.5 = -2.36
\n" ); document.write( "critical z at .95 one sided confidence interval is -1.65.
\n" ); document.write( "test z is greater than critical z, so test results are significant.
\n" ); document.write( "conclusion is that the percent of all persons exposed to a certain amount of radiation is less than 30%.\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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