document.write( "Question 1200370: Find the net change in the value of the function between the given inputs.\r
\n" ); document.write( "\n" ); document.write( "g(t) = 3 - t^2 ; from -5 to 6\r
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Algebra.Com's Answer #834488 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Plug in t = -5
\n" ); document.write( "g(t) = 3 - t^2
\n" ); document.write( "g(-5) = 3 - (-5)^2
\n" ); document.write( "g(-5) = 3 - 25
\n" ); document.write( "g(-5) = -22\r
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\n" ); document.write( "\n" ); document.write( "Plug in t = 6
\n" ); document.write( "g(t) = 3 - t^2
\n" ); document.write( "g(6) = 3 - 6^2
\n" ); document.write( "g(6) = 3 - 36
\n" ); document.write( "g(6) = -33\r
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\n" ); document.write( "\n" ); document.write( "Subtract the results
\n" ); document.write( "g(6) - g(-5) = -33 - (-22) = -33 + 22 = -11\r
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\n" ); document.write( "\n" ); document.write( "The net change is -11.
\n" ); document.write( "It means the output has gone down by 11 units when going from g(-5) = -22 to g(6) = -33.
\n" ); document.write( "Use a vertical number line to see why this is the case.
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\n" ); document.write( "You can think of -22 as being 22 feet below sea level, aka 22 feet underwater.
\n" ); document.write( "Move 11 feet further down and you will arrive at the marker -33 which represents being 33 feet underwater.
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