document.write( "Question 1200317: Suppose X has a Binomial distribution with n trials, and a probability of success p. The moment generating function for X has been shown to be
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document.write( "MX (t) = (pe^t + (1 − p))^n.
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document.write( "Using this result, find the distribution of the random variable Y for the following moment generating function.
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document.write( "MY (t) = (2+e^t)^5/3^5 \n" );
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Algebra.Com's Answer #834441 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Hint:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "I'll let the student finish up.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Side note: You should use parenthesis to indicate (2+e^t)^5 is over top 3^5 \n" ); document.write( "So you should write ((2+e^t)^5)/(3^5) \n" ); document.write( " \n" ); document.write( " |