document.write( "Question 1200322: In a survey, 10 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $36 and standard deviation of $4. Find the margin of error at a 95% confidence level.\r
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document.write( "Give your answer to three decimal places. \n" );
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Algebra.Com's Answer #834440 by math_tutor2020(3817) ![]() You can put this solution on YOUR website! \n" ); document.write( "Answer: 2.479\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Explanation:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "At 95% confidence, the z critical value is roughly z = 1.960 \n" ); document.write( "Use a calculator with built in stats functions (eg: TI84) or a reference table to determine this value.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here is one such table \n" ); document.write( "https://www.sjsu.edu/faculty/gerstman/StatPrimer/t-table.pdf \n" ); document.write( "Scroll to the bottom to locate 1.960, which is one cell above the \"95% confidence level\".\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The margin of error formula for the mean is \n" ); document.write( "E = z*sigma/sqrt(n) \n" ); document.write( "where,
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, \n" ); document.write( "E = z*sigma/sqrt(n) \n" ); document.write( "E = 1.960*4/sqrt(10) \n" ); document.write( "E = 2.479225685572 \n" ); document.write( "E = 2.479 \n" ); document.write( " \n" ); document.write( " |