document.write( "Question 1200322: In a survey, 10 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $36 and standard deviation of $4. Find the margin of error at a 95% confidence level.\r
\n" ); document.write( "\n" ); document.write( "Give your answer to three decimal places.
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Algebra.Com's Answer #834440 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Answer: 2.479\r
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\n" ); document.write( "\n" ); document.write( "Explanation:\r
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\n" ); document.write( "\n" ); document.write( "At 95% confidence, the z critical value is roughly z = 1.960
\n" ); document.write( "Use a calculator with built in stats functions (eg: TI84) or a reference table to determine this value.\r
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\n" ); document.write( "\n" ); document.write( "Here is one such table
\n" ); document.write( "https://www.sjsu.edu/faculty/gerstman/StatPrimer/t-table.pdf
\n" ); document.write( "Scroll to the bottom to locate 1.960, which is one cell above the \"95% confidence level\".\r
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\n" ); document.write( "\n" ); document.write( "The margin of error formula for the mean is
\n" ); document.write( "E = z*sigma/sqrt(n)
\n" ); document.write( "where,
  • z = critical value mentioned earlier = 1.960
  • sigma = standard deviation = 4
  • n = sample size = 10
Take note that the mean isn't involved with the margin of error formula.\r
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\n" ); document.write( "\n" ); document.write( "So,
\n" ); document.write( "E = z*sigma/sqrt(n)
\n" ); document.write( "E = 1.960*4/sqrt(10)
\n" ); document.write( "E = 2.479225685572
\n" ); document.write( "E = 2.479
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