document.write( "Question 1200320: Graph the equation using slope and y-intercept method.
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Algebra.Com's Answer #834427 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"-2y\"\"%22%22=%22%22\"\"x%2B6\"\r\n" );
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document.write( "First get the equation in slope-intercept form, y = mx + b, by\r\n" );
document.write( "solving for y\r\n" );
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document.write( "Give x the coefficient 1\r\n" );
document.write( "\"-2y\"\"%22%22=%22%22\"\"1%2Ax%2B6\"\r\n" );
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document.write( "Divide through by -2\r\n" );
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document.write( "\"%28-2y%29%2F%28-2%29\"\"%22%22=%22%22\"\"expr%281%2F%28-2%29%29%2Ax%2B6%2F%28-2%29\"\r\n" );
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document.write( "\"y\"\"%22%22=%22%22\"\"-expr%281%2F2%29%2Ax-3\"\r\n" );
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document.write( "Comparing that to y = mx + b we see that the slope m is \"-1%2F2\",\r\n" );
document.write( "and the y-intercept b is -3.\r\n" );
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document.write( "We plot the y-intercept at -3 on the y-axis:\r\n" );
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document.write( "Begin by looking at the numerator and sign of the slope.  The slope is \"-1%2F2\". \r\n" );
document.write( "Its numerator is 1, and its sign is -\r\n" );
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document.write( "Since the sign of the slope is NEGATIVE, we draw a line DOWNWARD from the \r\n" );
document.write( "y-intercept. It's the vertical blue line below.\r\n" );
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document.write( "[If the sign of the slope had been POSITIVE we would have drawn a line UPWARD].  \r\n" );
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document.write( "Next, we look at the denominator of the slope.  The slope is \"-1%2F2\". Its\r\n" );
document.write( "denominator is 2.  We always go to the RIGHT with the denominator.  So from\r\n" );
document.write( "the bottom of the blue line we draw a horizontal line to the right 2 units:\r\n" );
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document.write( "Now we take a straight edge and draw a line through the point where we started,\r\n" );
document.write( "at the y-intercept, and through the point where we ended up.\r\n" );
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document.write( "Edwin
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