document.write( "Question 1200292: The population of a town grows at a rate of e^1.2t-2t people per year (where t is the number of years). At t=2 years, the town has 1500 people. Approximately by how many people do the population grow between t=2 and t=5? What is the town’s population at t=5 year? \n" ); document.write( "

Algebra.Com's Answer #834426 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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\n" ); document.write( "Nobody seems to want this, here my effort, for what its worth, I don't know
\n" ); document.write( ":
\n" ); document.write( "The population of a town grows at a rate of $\"e%5E%281.2t%29+-+2t\"$ people per year (where t is the number of years).
\n" ); document.write( " At t=2 years, the town has 1500 people.
\n" ); document.write( " $\"f%28t-2%29+=+e%5E%281.2t%29+-+2t+%2B+1500\"$
\n" ); document.write( " Approximately by how many people do the population grow between t=2 and t=5?
\n" ); document.write( "t=2, 1500, t=5, 1900. 1900 - 1500 = 400 increase from yr 2 to yr 5
\n" ); document.write( " What is the town’s population at t=5 year?
\n" ); document.write( "Approx 1900 people \n" ); document.write( "

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