document.write( "Question 1200308: If Qasim has 4 times as many quarters as nickels and they have a combined value of 735 cents, how many of each coin does he have? \n" ); document.write( "
Algebra.Com's Answer #834410 by Theo(13342)\"\" \"About 
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25 * x + 5 * y = 735
\n" ); document.write( "x is the number of quarters; each quarter is worth 25 cents.
\n" ); document.write( "y is the number of nickels; each nickel is worth 5 cents.
\n" ); document.write( "you are given that x = 4 * y (4 times as many quarters as nickels)
\n" ); document.write( "your two equations are:
\n" ); document.write( "25 * x + 5 * y = 735
\n" ); document.write( "x = 4 * y
\n" ); document.write( "in the first equation, replace x with 4 * y to get:
\n" ); document.write( "25 * 4 * y + 5 * y = 735
\n" ); document.write( "simplify to get:
\n" ); document.write( "100 * y + 5 * y = 735
\n" ); document.write( "combine like terms to get:
\n" ); document.write( "105 * y = 735
\n" ); document.write( "solve for y to get:
\n" ); document.write( "y = 735 / 105 = 7
\n" ); document.write( "since x = 4 * y, then x = 28
\n" ); document.write( "25 * x becomes 25 * 28 = 700
\n" ); document.write( "5 * y becomes 5 * 7 = 35
\n" ); document.write( "25 * x + 5 * y becomes 700 + 35 = 735 cents.
\n" ); document.write( "solution is 28 quarters and 7 nickels.\r
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