document.write( "Question 1200288: On the campus of Central Louisiana College, a student survey found that 48%
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document.write( " of the students were born in Louisiana. Also, 26%
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document.write( " of the students were born in Louisiana and work part-time.\r
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document.write( "If a student is selected at random, find the probability that they work part-time, given that they were born in Louisiana. \n" );
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Algebra.Com's Answer #834391 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answer: 13/24 \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Work Shown: \n" ); document.write( "A = person was born in Louisiana \n" ); document.write( "B = person works part time \n" ); document.write( "P(A) = 0.48 is given \n" ); document.write( "P(A and B) = 0.26 is also given \n" ); document.write( "P(B given A) = P(A and B)/P(A) \n" ); document.write( "P(B given A) = 0.26/0.48 \n" ); document.write( "P(B given A) = 26/48 \n" ); document.write( "P(B given A) = 13/24 \n" ); document.write( "13/24 = 0.54166666666667 approximately \n" ); document.write( "Roughly 54.17% of the Louisiana-born students work part time. \n" ); document.write( " \n" ); document.write( " |