document.write( "Question 1200280: The polynomial of degree 5, P(x) has leading coefficient 1, has roots of multiplicity 2 at x=1 and x=0, and a root of multiplicity 1 at x=−3
\n" ); document.write( "Find a possible formula for P(x).
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Algebra.Com's Answer #834376 by math_tutor2020(3816)\"\" \"About 
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\n" ); document.write( "Answer: \"P%28x%29+=+x%5E2%28x-1%29%5E2%28x%2B3%29\"\r
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\n" ); document.write( "\n" ); document.write( "Explanation:
\n" ); document.write( "If k is a root of P(x), then x-k is a factor of P(x)
\n" ); document.write( "The multiplicity is the exponent for the factor.
\n" ); document.write( "So that's how for instance a root of x = 1 with multiplicity 2 leads to the factor \"%28x-1%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "The leading coefficient is the number out front of the variables.
\n" ); document.write( "For example, if the leading coefficient was 5, then we would have \"P%28x%29+=+5x%5E2%28x-1%29%5E2%28x%2B3%29\"\r
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\n" ); document.write( "\n" ); document.write( "Instead, the leading coefficient is 1 so we have \"P%28x%29+=+1x%5E2%28x-1%29%5E2%28x%2B3%29\" aka \"P%28x%29+=+x%5E2%28x-1%29%5E2%28x%2B3%29\"\r
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\n" ); document.write( "\n" ); document.write( "Optionally you can expand everything out to get \"P%28x%29+=+x%5E2%28x-1%29%5E2%28x%2B3%29+=+x%5E5%2Bx%5E4-5x%5E3%2B3x%5E2\"
\n" ); document.write( "However, I don't recommend doing this since it's unnecessary and you lose the information about the roots along with their multiplicities.
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