document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1200263>Question 1200263</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A pilot flew a jet from City A to City B, a distance of 1500 mi. On the return trip, the average speed was 20% faster than the outbound speed. The round-trip took 7 h 20 min. What was the speed from City A to City B? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #834357 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=834357\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is an alternative to the standard algebraic solution method shown by the other tutors.  For a particular similar problem, this alternative method might (or might not!) make the solution easier.<br><BR>\n" );
document.write( "The distances both directions are of course the same; and the ratio of the two speeds is 1:1.2, or 5:6.  That means the ratio of times at the two speeds was 6:5.<br><BR>\n" );
document.write( "The total time for the trip was 7 hours 20 minutes, or 440 minutes.  Dividing the 440 minutes in the ratio 6:5 gives 240 minutes for the flight at the lower speed from A to B and 200 minutes for the flight at the higher speed from B to A.<br><BR>\n" );
document.write( "The question asks for the speed on the flight from A to B, which was 1500 miles in 240 minutes, or 4 hours; the speed was 1500/4 = 375 mph.<br><BR>\n" );
document.write( "ANSWER: 375 mph<br><BR>\n" );
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