document.write( "Question 1200265: It took a crew 9 h 36 min to row 9 km upstream and back again. If the rate of flow of the stream was 7 km/h, what was the rowing speed of the crew in still water? \n" ); document.write( "
Algebra.Com's Answer #834342 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "9 hrs 36 min = 9.6 hrs
\n" ); document.write( "since 36 min = 36/60 = 0.6 hrs\r
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\n" ); document.write( "\n" ); document.write( "x = speed of the boat in still water
\n" ); document.write( "where x > 7\r
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\n" ); document.write( "\n" ); document.write( "When going upstream, the boat is slowed down to a speed of x-7 km/hr.
\n" ); document.write( "When going downstream, the boat is sped up to a speed of x+7 km/hr.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Upstream:
\n" ); document.write( "distance = rate*time
\n" ); document.write( "9 = (x-7)*t1
\n" ); document.write( "t1 = 9/(x-7)
\n" ); document.write( "It takes 9/(x-7) hours to row upstream.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Downstream:
\n" ); document.write( "distance = rate*time
\n" ); document.write( "9 = (x+7)*t2
\n" ); document.write( "t2 = 9/(x+7)
\n" ); document.write( "It takes 9/(x+7) hours to row downstream.\r
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\n" ); document.write( "\n" ); document.write( "The two time values (t1 and t2) must add to the total 9.6 hours mentioned earlier.
\n" ); document.write( "\"t%5B1%5D%2Bt%5B2%5D+=+9.6\"\r
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\n" ); document.write( "\n" ); document.write( "\"9%2F%28x-7%29%2B9%2F%28x%2B7%29+=+9.6\"\r
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\n" ); document.write( "\n" ); document.write( "\"9%28x%2B7%29%2B9%28x-7%29+=+9.6%28x-7%29%28x%2B7%29\" Multiply both sides by the LCD (x-7)(x+7) to clear out the fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"9%28x%2B7%29%2B9%28x-7%29+=+9.6%28x%5E2-49%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"9x%2B63%2B9x-63+=+9.6x%5E2-470.4\"\r
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\n" ); document.write( "\n" ); document.write( "\"18x+=+9.6x%5E2-470.4\"\r
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\n" ); document.write( "\n" ); document.write( "\"0+=+9.6x%5E2-470.4-18x\"\r
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\n" ); document.write( "\n" ); document.write( "\"9.6x%5E2-18x-470.4+=+0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"96x%5E2-180x-4704+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"12%288x%5E2-15x-392%29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"8x%5E2-15x-392+=+0\"
\n" ); document.write( "We have an equation in the form ax^2+bx+c = 0
\n" ); document.write( "a = 8
\n" ); document.write( "b = -15
\n" ); document.write( "c = -392
\n" ); document.write( "Plug those into the quadratic formula.
\n" ); document.write( "\"x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%28-15%29%2B-sqrt%28%28-15%29%5E2-4%288%29%28-392%29%29%29%2F%282%288%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2815%2B-sqrt%2812769%29%29%2F%2816%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%2815%2B-++113%29%2F%2816%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%2815%2B113%29%2F%2816%29\" or \"x+=+%2815-113%29%2F%2816%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28128%29%2F%2816%29\" or \"x+=+%28-98%29%2F%2816%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+8\" or \"x+=+-6.125\"
\n" ); document.write( "A negative speed value doesn't make sense, so we ignore \"x+=+-6.125\"
\n" ); document.write( "The only practical answer is \"x+=+8\"\r
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\n" ); document.write( "\n" ); document.write( "Answer: The speed of the boat in still water is 8 km/hr.
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