document.write( "Question 114678: Solve by using the quadratic formula:\r
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Algebra.Com's Answer #83434 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let's use the quadratic formula to solve for z:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"az%5E2%2Bbz%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"9%2Az%5E2%2B12%2Az%2B4=0\" ( notice \"a=9\", \"b=12\", and \"c=4\")\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-12+%2B-+sqrt%28+%2812%29%5E2-4%2A9%2A4+%29%29%2F%282%2A9%29\" Plug in a=9, b=12, and c=4\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-12+%2B-+sqrt%28+144-4%2A9%2A4+%29%29%2F%282%2A9%29\" Square 12 to get 144 \r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-12+%2B-+sqrt%28+144%2B-144+%29%29%2F%282%2A9%29\" Multiply \"-4%2A4%2A9\" to get \"-144\"\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-12+%2B-+sqrt%28+0+%29%29%2F%282%2A9%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-12+%2B-+0%29%2F%282%2A9%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-12+%2B-+0%29%2F18\" Multiply 2 and 9 to get 18\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-12+%2B+0%29%2F18\" or \"z+=+%28-12+-+0%29%2F18\"\r
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\n" ); document.write( "\n" ); document.write( "Lets look at the first part:\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-12+%2B+0%29%2F18\"\r
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\n" ); document.write( "\n" ); document.write( "\"z=-12%2F18\" Add the terms in the numerator\r
\n" ); document.write( "\n" ); document.write( "\"z=-2%2F3\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So one answer is\r
\n" ); document.write( "\n" ); document.write( "\"z=-2%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "Now lets look at the second part:\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-12+-+0%29%2F18\"\r
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\n" ); document.write( "\n" ); document.write( "\"z=-12%2F18\" Subtract the terms in the numerator\r
\n" ); document.write( "\n" ); document.write( "\"z=-2%2F3\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So another answer is\r
\n" ); document.write( "\n" ); document.write( "\"z=-2%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "So our only solution is:\r
\n" ); document.write( "\n" ); document.write( "\"z=-2%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "Notice when we graph \"9%2Ax%5E2%2B12%2Ax%2B4\" (just replace z with x), we get:\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-12%2C+8%2C+-12%2C+8%2C9%2Ax%5E2%2B12%2Ax%2B4%29+\"\r
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\n" ); document.write( "\n" ); document.write( "and we can see that the roots is \"x=-2%2F3\". This verifies our answer
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