document.write( "Question 114676: Solve by using the quadratic formula:\r
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Algebra.Com's Answer #83433 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let's use the quadratic formula to solve for z:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"az%5E2%2Bbz%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"z%5E2%2B4%2Az%2B1=0\" ( notice \"a=1\", \"b=4\", and \"c=1\")\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-4+%2B-+sqrt%28+%284%29%5E2-4%2A1%2A1+%29%29%2F%282%2A1%29\" Plug in a=1, b=4, and c=1\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-4+%2B-+sqrt%28+16-4%2A1%2A1+%29%29%2F%282%2A1%29\" Square 4 to get 16 \r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-4+%2B-+sqrt%28+16%2B-4+%29%29%2F%282%2A1%29\" Multiply \"-4%2A1%2A1\" to get \"-4\"\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-4+%2B-+sqrt%28+12+%29%29%2F%282%2A1%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-4+%2B-+2%2Asqrt%283%29%29%2F%282%2A1%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-4+%2B-+2%2Asqrt%283%29%29%2F2\" Multiply 2 and 1 to get 2\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-4+%2B+2%2Asqrt%283%29%29%2F2\" or \"z+=+%28-4+-+2%2Asqrt%283%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Now break up the fraction\r
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\n" ); document.write( "\n" ); document.write( "\"z=-4%2F2%2B2%2Asqrt%283%29%2F2\" or \"z=-4%2F2-2%2Asqrt%283%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"z=-2%2Bsqrt%283%29\" or \"z=-2-sqrt%283%29\"\r
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\n" ); document.write( "\n" ); document.write( "So these expressions approximate to\r
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\n" ); document.write( "\n" ); document.write( "\"z=-0.267949192431123\" or \"z=-3.73205080756888\"\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"z=-0.267949192431123\" or \"z=-3.73205080756888\"\r
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\n" ); document.write( "\n" ); document.write( "Notice when we graph \"x%5E2%2B4%2Ax%2B1\" (just replace z with x), we get:\r
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\n" ); document.write( "\n" ); document.write( "when we use the root finder feature on a calculator, we find that \"x=-0.267949192431123\" and \"x=-3.73205080756888\".So this verifies our answer\r
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