document.write( "Question 114675: Marina leaves home at 9AM, bicycling at a rate at 24 mi/h. Two hours later, John leaves driving at the rate of 48 mi/h. At what time will John catch up with Marina? \n" ); document.write( "
Algebra.Com's Answer #83431 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Marina leaves home at 9AM, bicycling at a rate at 24 mi/h. Two hours later, John leaves driving at the rate of 48 mi/h. At what time will John catch up with Marina? \n" ); document.write( "---------------- \n" ); document.write( "Marina DATA: \n" ); document.write( "Rate = 24 mph ; Time = x hrs ; Distance = rt = 24x miles \n" ); document.write( "------------------------- \n" ); document.write( "John DATA: \n" ); document.write( "Rate = 48 mph ; Time = x-2 hrs ; Distance = rt = 48(x-2) miles \n" ); document.write( "--------------------- \n" ); document.write( "EQUATION: \n" ); document.write( "distance = distance \n" ); document.write( "24x = 48(x-2) \n" ); document.write( "x = 2(x-2) \n" ); document.write( "x = 4 hrs (Marina's Time) \n" ); document.write( "------------------- \n" ); document.write( "9AM + 4 hrs = 1PM \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |