document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1200226>Question 1200226</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Benjamin is drawing a triangle <BR>\n" );
document.write( "and knows that two sides are <BR>\n" );
document.write( "9 centimeters and 12 centimeters. <BR>\n" );
document.write( "What could the third side length be? <BR>\n" );
document.write( "Select all that apply<BR>\n" );
document.write( "2 cm<BR>\n" );
document.write( "4 cm<BR>\n" );
document.write( "10 cm<BR>\n" );
document.write( "18 cm<BR>\n" );
document.write( "21 cm </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #834291 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=834291\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "In any triangle, the sum of the lengths of the two shorter sides must be greater than the length of the longest side.<br><BR>\n" );
document.write( "If the side with length 12cm is the longest, then the missing side must have length x where 9 plus x is greater than 12.<br><BR>\n" );
document.write( "If the missing side is the longest side, then its length x must be such that 9 plus 12 is greater than x.<br><BR>\n" );
document.write( "Now you answer the question.<br><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );