document.write( "Question 114659: I have tried everything and I just don't understand this problem.
\n" ); document.write( "Here is the problem \r
\n" ); document.write( "\n" ); document.write( "\"log%286%2C36%29\" = \"5x+%2B+3\"\r
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Algebra.Com's Answer #83429 by edjones(8007)\"\" \"About 
You can put this solution on YOUR website!
log(6)36=(5x+3)
\n" ); document.write( "36=6^(5x+3)
\n" ); document.write( "6^2=6^(5x+3)
\n" ); document.write( "Since the base (6) is the same for all exponents we can make an equation of the exponents:
\n" ); document.write( "2=5x+3
\n" ); document.write( "5x=-1
\n" ); document.write( "x=-1/5
\n" ); document.write( "Check:
\n" ); document.write( "2=5*-1/5+3
\n" ); document.write( "2=-1+3 true
\n" ); document.write( "Ed
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