document.write( "Question 1200225: Last year, Carlos had $30,000 to invest. He invested some of it in account that paid 10% simple interest per year, and he invested the rest in an account that paid 5% simple interest per year. After one year, he received a total of $2500 in interest. How much did he invest in each account?
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Algebra.Com's Answer #834289 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "With formal algebra.... \n" ); document.write( "x = amount invested at 10% \n" ); document.write( "30000-x = amount at 5% \n" ); document.write( "The total interest was $2500: \n" ); document.write( ".10(x)+.05(30000-x) = 2500 \n" ); document.write( "Solve using basic algebra... I leave that to you. \n" ); document.write( "Informally, if a formal algebraic solution is not required.... \n" ); document.write( "All $30000 invested at 5% would have returned $1500 interest; all at 10% would have returned $3000 interest. \n" ); document.write( "The actual interest $2500 is 2/3 of the way from $1500 to $3000. \n" ); document.write( "That means 2/3 of the total was invested at the higher rate. \n" ); document.write( "ANSWER: 2/3 of the $30000, or $20000, at 10%; the other $10000 at 5% \n" ); document.write( "CHECK: .10($20000)+.05($10000) = $2000+$500 = $2500 \n" ); document.write( " \n" ); document.write( " |