document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=114670>Question 114670</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangular playing field is 5 feet less than twice its width. If the perimeter of the playing field is 230 feet, find the length and width of the field. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #83428 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=83428\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangular playing field is 5 feet less than twice its width. If the perimeter of the playing field is 230 feet, find the length and width of the field.<BR>\n" );
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document.write( "Let the width be \"x\" ft.<BR>\n" );
document.write( "Then length = \"2x-5\" ft.<BR>\n" );
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document.write( "Perimeter = 2(length + width)<BR>\n" );
document.write( "230 = 2(3x-5)<BR>\n" );
document.write( "115 = 3x-5<BR>\n" );
document.write( "3x = 120<BR>\n" );
document.write( "x = 40 ft (this is the width)<BR>\n" );
document.write( "2x-5 = 75 ft ( this is the length)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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