document.write( "Question 1200217: A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y=9−x2. What are the dimensions of such a rectangle with the greatest possible area? \n" ); document.write( "
Algebra.Com's Answer #834278 by ikleyn(52874)\"\" \"About 
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\n" ); document.write( "A rectangle is inscribed with its base on the x-axis and its upper corners
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document.write( "The area of any such inscribed rectangle is \r\n" );
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document.write( "    A = A(x) = base*height = (2x)*y = 2x*(9-x^2) = 18x - 2x^3.\r\n" );
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document.write( "We want maximize the area A(x), i.e. maximize function A(x).\r\n" );
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document.write( "So, we take the derivative and equate it to zero\r\n" );
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document.write( "    A'(x) = 18 - 6x^2 = 0.\r\n" );
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document.write( "From this equation, we find\r\n" );
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document.write( "    6x^2 = 18  --->  x^2 = 18/6 = 3  --->  x = \"sqrt%283%29\".\r\n" );
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document.write( "The dimensions of the inscribed rectangle are  \"2%2Asqrt%283%29\"  horizontally\r\n" );
document.write( "and  \"9+-+%28sqrt%283%29%29%5E2\" = 9 - 3 = 6 units vertically.\r\n" );
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document.write( "The maximum area is  xy = \"2%2A6%2Asqrt%283%29\" = \"12%2Asqrt%283%29\"  square units.\r\n" );
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