document.write( "Question 1199998: In the diagram, Angle A = 40° while BD and CD are the bisectors of
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Algebra.Com's Answer #834241 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "In the diagram, Angle A = 40° while BD and CD are the bisectors of
\n" ); document.write( "angles EBC and FCB respectively. Find the measure of angle D. \r
\n" ); document.write( "\n" ); document.write( "https://ibb.co/2My3RKd\r
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Let ∡ACB be xo\r\n" );
document.write( "Then ∡ABC = 180 - (40 + x) = (140 - x)o\r\n" );
document.write( "Therefore, ∡FCB = (180 - x)o, and ∡EBC = 180 - (140 - x) = (40 + x)o\r\n" );
document.write( "As BD bisects ∡EBC, ∡DBC = \"matrix%281%2C3%2C+%2840+%2B+x%29%2F2%2C+%22or%22%2C+20+%2B+x%2F2%29\" \r\n" );
document.write( "Likewise, since DC bisects ∡FCB, ∡DCB = \"matrix%281%2C3%2C+%28180+-+x%29%2F2%2C+%22or%22%2C+90+-+x%2F2%29\" \r\n" );
document.write( "Thus ∡D = 
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