document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1200109>Question 1200109</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jesse rode his bike for 2 hours at a constant rate. During the first 1.5 hours, he rode 9 miles. How many miles did Jesse ride his bike during the last half hour? (Enter an exact number.)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #834134 by </B><A HREF=/tutors/aboutme.mpl?userid=jadams><B>jadams(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jadams><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=834134\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> distance = rate * time. We're given time = 3/2 hrs for distance 9 miles...\r<BR>\n" );
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document.write( "d = r*t, divide both sides by t to change formula to solve for rate: r*t/t = d/t,<BR>\n" );
document.write( "r = d/t.\r<BR>\n" );
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document.write( "r = 9/3/2 distance 9 divided by 3/2 hr.\r<BR>\n" );
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document.write( "r = 9/1 miles divided by 3 half hrs (3/2),  invert and multiply  9/1 * 2/3\r<BR>\n" );
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document.write( "r = cross divide to get 3/1 * 2/1 = 6 mi. per hr.\r<BR>\n" );
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document.write( "We're told Jesse rode at a constant rate so during the last 1/2 hr he<BR>\n" );
document.write( "traveled 6/2 miles or 3 miles. </SPAN>\n" );
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