document.write( "Question 1200106: Find all horizontal and vertical asymptotes of the function: f(x) = x/sqrt(x^2-1)
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Algebra.Com's Answer #834132 by Edwin McCravy(20056)\"\" \"About 
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document.write( "\"%22f%28x%29%22\"\"%22%22=%22%22\"\"x%5E%22%22%2Fsqrt%28x%5E2-1%29\"\r\n" );
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document.write( "To find vertical asymptotes, set the denominator equal to 0:\r\n" );
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document.write( "\"sqrt%28x%5E2-1%29\"\"%22%22=%22%22\"\"0\"\r\n" );
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document.write( "\"x%5E2-1\"\"%22%22=%22%22\"\"0\"\r\n" );
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document.write( "\"%28x-1%29%28x%2B1%29\"\"%22%22=%22%22\"\"0\"\r\n" );
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document.write( "x-1 = 0;  x+1 = 0\r\n" );
document.write( "  x = 1;    x = -1\r\n" );
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document.write( "So the vertical asymptotes are the vertical lines whose equations are\r\n" );
document.write( "x = 1  and x = -1\r\n" );
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document.write( "To find the horizontal asymptotes we substitute large positive and negative\r\n" );
document.write( "numbers for x, and see if they approach any finite number.\r\n" );
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document.write( "Substituting x = 1000,\r\n" );
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document.write( "\"%22f%281000%29%22\"\"%22%22=%22%22\"\"%281000%5E%22%22%29%2Fsqrt%281000%5E2-1%29\"\"%22%22=%22%22\"\"1.0000005\"\r\n" );
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document.write( "That is very close to 1, so we assume y = 1 is a horizontal asymptote.\r\n" );
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document.write( "Substituting x = -1000,\r\n" );
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document.write( "\"%22f%28-1000%29%22\"\"%22%22=%22%22\"\"%28-1000%29%5E%22%22%2Fsqrt%28%28-1000%29%5E2-1%29\"\"%22%22=%22%22\"\"-1.0000005\"\r\n" );
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document.write( "That is very close to -1, so we assume y = -1 is also a horizontal asymptote.\r\n" );
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document.write( "So we draw the vertical asymptotes x = 1 and x= -1 and horizontal asymptotes \r\n" );
document.write( "are y = 1 and y = -1\r\n" );
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document.write( "Since the function contains a square root, we must ensure that what's under the\r\n" );
document.write( "square root is greater than 0.\r\n" );
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document.write( "\"x%5E2-1%3E=0\"\r\n" );
document.write( "\"%28x-1%29%28x%2B1%29%3E=0\"\r\n" );
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document.write( "They have zeros 1 and -1.  We make a number line\r\n" );
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document.write( "----------o-----o---------\r\n" );
document.write( "-4 -3 -2 -1  0  1  2  3  4 \r\n" );
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document.write( "Choose test point x=-2 in interval \"%28matrix%281%2C3%2C-infinity%2C+%22%2C%22%2C+-1%29%29\"\r\n" );
document.write( "\"%28x-1%29%28x%2B1%29%3E=0\"\r\n" );
document.write( "\"%28-2-1%29%28-2%2B1%29%3E=0\"\r\n" );
document.write( "\"%28-3%29%28-1%29%3E=0\"\r\n" );
document.write( "\"3%3E=0\"\r\n" );
document.write( "That is a true inequality, so \"%28matrix%281%2C3%2C-infinity%2C+%22%2C%22%2C+-1%29%29\" is part of\r\n" );
document.write( "the domain.\r\n" );
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document.write( "Choose test point x=0 in interval \"%28matrix%281%2C3%2C-1%2C+%22%2C%22%2C+1%29%29\"\r\n" );
document.write( "\"%28x-1%29%28x%2B1%29%3E=0\"\r\n" );
document.write( "\"%280-1%29%280%2B1%29%3E=0\"\r\n" );
document.write( "\"%28-1%29%281%29%3E=0\"\r\n" );
document.write( "\"-1%3E=0\"\r\n" );
document.write( "That is a false inequality, so \"%28matrix%281%2C3%2C-1%2C+%22%2C%22%2C+1%29%29\" is NOT part of\r\n" );
document.write( "the domain.  Therefore there is no graph between where x=-1 and where x=1.\r\n" );
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document.write( "Choose test point x=2 in interval \"%28matrix%281%2C3%2C1%2C+%22%2C%22%2C+infinity%29%29\"\r\n" );
document.write( "\"%28x-1%29%28x%2B1%29%3E=0\"\r\n" );
document.write( "\"%282-1%29%282%2B1%29%3E=0\"\r\n" );
document.write( "\"%281%29%283%29%3E=0\"\r\n" );
document.write( "\"3%3E=0\"\r\n" );
document.write( "That is a true inequality, so \"%28matrix%281%2C3%2C1%2C+%22%2C%22%2C+infinity%29%29\" is part of\r\n" );
document.write( "the domain.  So the shaded number line is\r\n" );
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document.write( "<==========o-----o=========>\r\n" );
document.write( " -4 -3 -2 -1  0  1  2  3  4 \r\n" );
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document.write( "So the domain is  \r\n" );
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document.write( "We find a couple points in both parts of the domain, say the points \r\n" );
document.write( "(-2,-1.2) and (2,1.2).  Then sketch the graph:\r\n" );
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document.write( "Edwin
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