document.write( "Question 1200102: Find three consecutive even integers such that the product of the first and second is 20 less than 10 times the third \n" ); document.write( "

Algebra.Com's Answer #834122 by josgarithmetic(39620) $\"\"$ $\"About$

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n, n+2, n+4\r
\n" ); document.write( "\n" ); document.write( " $\"n%28n%2B2%29=10%28n%2B4%29-20\"$ \r
\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( " $\"n%5E2%2B2n=10n%2B40-20\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"n%5E2-8n=20\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"n%28n-8%29=20\"$
\n" ); document.write( "Try to avoid quadratic formula general solution method.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Two factors differing by 8 to give product 20:
\n" ); document.write( " 10 and 2.
\n" ); document.write( "n=10.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The consecutive even integers: 10, 12, 14. \n" ); document.write( "

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