document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1200041>Question 1200041</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If Jasmine has 4 more dimes than nickels and they have a combined value of 145 cents, how many of each coin does she have?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #834059 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13203)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=834059\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Probably a formal algebraic solution was wanted; the other tutors showed a couple.<br><BR>\n" );
document.write( "But you can get some good mental exercise, and good problem-solving practice, by solving the problem using logical reasoning and simple mental arithmetic -- something like this:<br><BR>\n" );
document.write( "(1) take away the \"extra\" 4 dimes, leaving equal numbers of nickels and dimes, with a total value of 145-40 = 105 cents<BR>\n" );
document.write( "(2) one nickel and one dime together have a value of 15 cents; the number of nickels and dimes required to make 105 cents is 105/15 = 7<BR>\n" );
document.write( "(3) that makes 7 nickels and 7 dimes; now add back in the other 4 dimes to give the final answer of 7 nickels and 11 dimes<br><BR>\n" );
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