document.write( "Question 1199909: Find the pair of integers (a,b) for which 2^a+1 + 2^a = 3^b+2 - 3^b \n" ); document.write( "
Algebra.Com's Answer #834054 by math_tutor2020(3816)\"\" \"About 
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\n" ); document.write( "I'm assuming the equation is
\n" ); document.write( "\"2%5E%28a%2B1%29%2B2%5Ea+=+3%5E%28b%2B2%29-3%5Eb\"
\n" ); document.write( "which is equivalent to writing out 2^(a+1)+2^a = 3^(b+2)-3^b
\n" ); document.write( "Use parenthesis for the exponents \"a+1\" and \"b+2\"\r
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\n" ); document.write( "\n" ); document.write( "If my initial assumption is correct, then,
\n" ); document.write( "\"2%5E%28a%2B1%29%2B2%5Ea+=+3%5E%28b%2B2%29-3%5Eb\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%5Ea%2A2%5E1%2B2%5Ea+=+3%5Eb%2A3%5E2-3%5Eb\" Use the rule a^(b+c) = a^b*a^c\r
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\n" ); document.write( "\n" ); document.write( "\"2%5Ea%2A2%2B2%5Ea+=+3%5Eb%2A9-3%5Eb\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%5Ea%2A%282%2B1%29+=+3%5Eb%2A%289-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%5Ea%2A%283%29+=+3%5Eb%2A%288%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"3%2A2%5Ea+=+8%2A3%5Eb\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%5Ea%2A%281%2F8%29+=+3%5Eb%2A%281%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%5Ea%2A2%5E%28-3%29+=+3%5Eb%2A3%5E%28-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%5E%28a-3%29+=+3%5E%28b-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "Because the bases are different, the two sides are only equal when the exponents are zero (to make both sides to simplify to 1).
\n" ); document.write( "a-3 = 0 leads to a = 3
\n" ); document.write( "b-1 = 0 leads to b = 1
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