document.write( "Question 1200014: A simple gambling game involves the throw of a die. Players are charged 40 cents if the die shows 1,2 or 3 they are charged nothing for 4 and they receive 30 cents or 60 cents respectively for 5 or 6. Let the random variable X be the payout to the player.
\n" ); document.write( "Calculate the expected value and how much profit would the casino expect to make on 100 games?\r
\n" ); document.write( "\n" ); document.write( "If the backer weighted the die so that it is 50% more likely to turn up each of the results 1,2,3 as to turn up 4,5 or 6.
\n" ); document.write( "What is the probability now of each outcome?
\n" ); document.write( "Find expected value now.
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Algebra.Com's Answer #834021 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Problem 1: A simple gambling game involves the throw of a die.
\n" ); document.write( "Players are charged 40 cents if the die shows 1,2 or 3 they are charged nothing for 4 and they receive 30 cents or 60 cents respectively for 5 or 6.
\n" ); document.write( "Let the random variable X be the payout to the player.
\n" ); document.write( "Calculate the expected value and how much profit would the casino expect to make on 100 games?
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\n" ); document.write( "\n" ); document.write( "X = payout, in cents, to the player
\n" ); document.write( "X can take on the following values: {-40,0,30,60}
\n" ); document.write( "The negative value is where the player loses money.\r
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\n" ); document.write( "\n" ); document.write( "The probability of rolling a 1, 2 or 3 is 3/6.
\n" ); document.write( "This is the probability of X = -40 happening.\r
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\n" ); document.write( "\n" ); document.write( "The probability of rolling a 4 is 1/6 because there's one side labeled \"4\" out of 6 sides total.
\n" ); document.write( "This is when X = 0\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The probability of rolling a 5 is also 1/6.
\n" ); document.write( "This is the probability of X = 30 happening.\r
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\n" ); document.write( "\n" ); document.write( "The probability of rolling a 6 is also 1/6.
\n" ); document.write( "This is the probability of X = 60 happening.\r
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\n" ); document.write( "\n" ); document.write( "Let's set up a table with each X and P(X) value.
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XP(X)
-403/6
01/6
301/6
601/6
\r
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\n" ); document.write( "\n" ); document.write( "Now multiply across the rows to form the X*P(X) column.
\n" ); document.write( "Example: -40 times 3/6 = -120/6
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XP(X)X*P(X)
-403/6-120/6
01/60/6
301/630/6
601/660/6
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\n" ); document.write( "\n" ); document.write( "Add the items in that third column to get the expected payout.
\n" ); document.write( "(-120/6)+(0/6)+(30/6)+(60/6)
\n" ); document.write( "= (-120+0+30+60)/6
\n" ); document.write( "= -30/6
\n" ); document.write( "= -5\r
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\n" ); document.write( "\n" ); document.write( "A negative payout means the player lost money.
\n" ); document.write( "The player expects to lose, on average, 5 cents per game.
\n" ); document.write( "From the perspective of the casino, they are winning 5 cents per game on average.\r
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\n" ); document.write( "\n" ); document.write( "Over the course of 100 games, the casino would expect to gain 100*5 = 500 cents = $5
\n" ); document.write( "Or the calculation would be 100*(0.05 dollars) = 5 dollars.\r
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\n" ); document.write( "\n" ); document.write( "Answers:
\n" ); document.write( "Expected payout per game = -5 cents (perspective of the player)
\n" ); document.write( "Casino profit on one hundred games = $5\r
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\n" ); document.write( "\n" ); document.write( "Problem 2: If the backer weighted the die so that it is 50% more likely to turn up each of the results 1,2,3 as to turn up 4,5 or 6.
\n" ); document.write( "What is the probability now of each outcome?
\n" ); document.write( "Find expected value now.
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\n" ); document.write( "\n" ); document.write( "50% more likely involves the multiplier 1.5, which converts to 3/2.\r
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\n" ); document.write( "\n" ); document.write( "Rolling a 1,2, or 3 initially had probability 3/6 aka 1/2.\r
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\n" ); document.write( "\n" ); document.write( "Increase that by 50% to get (1.5)*(1/2) = (3/2)*(1/2) = 3/4\r
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\n" ); document.write( "\n" ); document.write( "Therefore, event X = -40 has probability P(X) = 3/4\r
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\n" ); document.write( "\n" ); document.write( "On this weighted die, rolling a 1,2, or 3 has probability 3/4.
\n" ); document.write( "That means 1-3/4 = 1/4 is the leftover amount for the other values\r
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\n" ); document.write( "\n" ); document.write( "Split that remaining bit into three equal pieces: (1/4)*(1/3) = 1/12
\n" ); document.write( "Rolling a 4 has probability 1/12
\n" ); document.write( "Rolling a 5 has probability 1/12
\n" ); document.write( "Rolling a 6 has probability 1/12\r
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\n" ); document.write( "\n" ); document.write( "The event X = 0 has probability 1/12
\n" ); document.write( "The event X = 30 has probability 1/12
\n" ); document.write( "The event X = 60 has probability 1/12
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XP(X)
-403/4
01/12
301/12
601/12
\r
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\n" ); document.write( "\n" ); document.write( "For the sake of consistency, let's get each denominator to 12.
\n" ); document.write( "3/4 = (3/4)*(3/3) = 9/12
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XP(X)
-409/12
01/12
301/12
601/12
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\n" ); document.write( "\n" ); document.write( "Now form the X*P(X) column
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XP(X)X*P(X)
-409/12-360/12
01/120/12
301/1230/12
601/1260/12
\r
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\n" ); document.write( "\n" ); document.write( "Add the X*P(X) items
\n" ); document.write( "(-360/12)+(0/12)+(30/12)+(60/12)
\n" ); document.write( "= (-360+0+30+60)/12
\n" ); document.write( "= -270/12
\n" ); document.write( "= -22.50\r
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\n" ); document.write( "\n" ); document.write( "The player expects to lose, on average, 22.50 cents per game.
\n" ); document.write( "The casino expects to gain, on average, 22.50 cents per game.\r
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\n" ); document.write( "\n" ); document.write( "Playing 100 games means the casino expects to make 0.225*100 = 22.50 dollars\r
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\n" ); document.write( "\n" ); document.write( "Answers:
\n" ); document.write( "The probability of each outcome is shown in the table above
\n" ); document.write( "Expected payout for the player = -22.5 cents
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