document.write( "Question 1199998: In the diagram, Angle A = 40° while BD and CD are the bisectors of
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Algebra.Com's Answer #834019 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "In the diagram, Angle A = 40° while BD and CD are the bisectors of
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document.write( "The sum of angles ABC and ACB is 180° - 40° = 140°.\r\n" );
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document.write( "The angles EBC and FCB are outer angles of the triangle ABC to angles ABC and ACB, respectively.\r\n" );
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document.write( "Therefore, the sum of angles EBC and FCB is \r\n" );
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document.write( "    (180°- < ABC) + (180° - < FCB) = 360° - 140° = 220°.\r\n" );
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document.write( "Angles CBD and DCB are halves of angles EBC and FCB;\r\n" );
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document.write( "therefore, < CBD + < DCB = 220°/2 = 110°.\r\n" );
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document.write( "It implies that angle D is  180° - 110° = 70°.    ANSWER\r\n" );
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document.write( "ANSWER.  The angle D measure is 70°.\r\n" );
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