document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1199999>Question 1199999</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am thinking of a number, when divided by 9 the remainder is 4. When divided by 5 the remainder is 4 and when divided by 3 the remainder is 1. What number am I thinking of?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #834005 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=834005\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The given information that the number divided by 3 leaves remainder 1 is superfluous, because 9 is a multiple of 3 and the remainder when divided by 9 is 4.<br><BR>\n" );
document.write( "So the simplified problem is to find a number that leaves remainder 4 when divided by either 5 or 9.  But if the remainder is 4 when divided by either 5 or 9, then the remainder is 4 when divided by 5*9=45.<br><BR>\n" );
document.write( "So the given number could be any number that is 4 more than a multiple of 45.<br><BR>\n" );
document.write( "One simple obvious such number is 4+45 = 49.<br><BR>\n" );
document.write( "But other possibilities are 4+2(45) = 94, or 4+10(45) = 454, or even 4+(-3)(45) = -131.<br><BR>\n" );
document.write( "ANSWER (the PROBABLE expected one): 49<br><BR>\n" );
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