document.write( "Question 1199966: Given: sin(x) - cos(x) = 1/(5^1/2) find the value of tan(x) + cot(x) + cos(2x) \n" ); document.write( "
Algebra.Com's Answer #833978 by ikleyn(52817)\"\" \"About 
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\n" ); document.write( "Given: sin(x) - cos(x) = 1/(5^1/2) find the value of tan(x) + cot(x) + cos(2x)
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document.write( "The given equality  sin(x) - cos(x) = \"1%2Fsqrt%285%29\"  implies after squaring\r\n" );
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document.write( "    sin^2(x) - 2sin(x)*cos(x) + cos^2(x) = \"1%2F5\"\r\n" );
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document.write( "    1 - sin(2x) = \"1%2F5\"\r\n" );
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document.write( "    1 - \"1%2F5\" = sin(2x)\r\n" );
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document.write( "    sin(2x) = \"4%2F5\".      (1)\r\n" );
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document.write( "The value of  tan(x) + cot(x) + cos(2x) is\r\n" );
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document.write( "      \"sin%28x%29%2Fcos%28x%29\" + \"cos%28x%29%2Fsin%28x%29\" + cos(2x) = \r\n" );
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document.write( "    = \"%28sin%5E2%28x%29+%2B+cos%5E2%28x%29%29%2F%28sin%28x%29%2Acos%28x%29%29\" + cos(2x) = \r\n" );
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document.write( "    = \"2%2Fsin%282x%29\" + cos(2x).\r\n" );
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document.write( "Substitute here sin(2x) = \"4%2F5\"  and  cos(2x) = \"sqrt%281-sin%5E2%282x%29%29\" = \"sqrt%281-%284%2F5%29%5E2%29\" = \"3%2F5\",  based on (1).  You will get\r\n" );
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document.write( "    tan(x) + cot(x) + cos(2x) = \"2%2F%28%284%2F5%29%29\" + \"3%2F5\" = \"10%2F4\" + \"3%2F5\" = \"%285%2A10%29%2F20\" + \"%284%2A3%29%2F20\" = \r\n" );
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document.write( "                              = \"%2850%2B12%29%2F20\" = \"62%2F20\" = \"31%2F10\" = 3.1.    ANSWER\r\n" );
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document.write( "ANSWER.  If  sin(x) - cos(x) = \"1%2Fsqrt%285%29\"  then  tan(x) + cot(x) + cos(2x) = \"31%2F10\" = 3.1.\r\n" );
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