document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1199930>Question 1199930</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Evaluate sqrt[12+sqrt(12+sqrt(12+...]\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #833916 by </B><A HREF=/tutors/aboutme.mpl?userid=TonyChopper><B>TonyChopper(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=TonyChopper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=833916\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sqrt[12+sqrt(12+sqrt(12+...] can be shown as x = sqrt(12+x)\r<BR>\n" );
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document.write( "When both sides are squared, the equation becomes x^2 = 12 + x\r<BR>\n" );
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document.write( "x^2 = 12 + x<BR>\n" );
document.write( "0 = x^2 + x + 12<BR>\n" );
document.write( "0 = (x+3)(x-4)\r<BR>\n" );
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document.write( "In order for the equation to hold true, x must either be -3, or 4\r<BR>\n" );
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document.write( "If we substitute -3 and 4 into x = sqrt(12+x), we find that -3 does not satisfy our equation while 4 does. \r<BR>\n" );
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document.write( "Therefore sqrt[12+sqrt(12+sqrt(12+...] is equal to 4 \r<BR>\n" );
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