document.write( "Question 1199890: A total of $7000 is deposited into two simple interest accounts. In one account the annual simple interest rate is 3%, and in the second account the annual simple interest rate is 7%. The amount of interest earned for 1 year was $250. How much was invested in each account? \n" ); document.write( "
Algebra.Com's Answer #833867 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "The simple interest formula is
\n" ); document.write( "i = P*r*t
\n" ); document.write( "where,
\n" ); document.write( "i = interest
\n" ); document.write( "P = deposit
\n" ); document.write( "r = interest rate in decimal form
\n" ); document.write( "t = number of years\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let
\n" ); document.write( "x = amount deposited at 3% rate
\n" ); document.write( "7000-x = amount deposited at 7% rate
\n" ); document.write( "The two items add to $7000\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "For the 3% account
\n" ); document.write( "i = P*r*t
\n" ); document.write( "i = x*0.03*1
\n" ); document.write( "i = 0.03x\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "For the 7% account
\n" ); document.write( "i = P*r*t
\n" ); document.write( "i = (7000-x)*0.07*1
\n" ); document.write( "i = 490-0.07x\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Total interest = 0.03x+(490-0.07x)
\n" ); document.write( "Total interest = -0.04x+490\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Set that equal to $250 and solve for x.
\n" ); document.write( "Total interest = 250
\n" ); document.write( "-0.04x+490 = 250
\n" ); document.write( "-0.04x = 250-490
\n" ); document.write( "-0.04x = -240
\n" ); document.write( "x = -240/(-0.04)
\n" ); document.write( "x = 6000
\n" ); document.write( "$6000 was invested at 3% interest rate.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Then use mental math to determine the remaining amount invested must be $1000\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Or you can say: 7000-x = 7000-6000 = 1000\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "6000+1000 = 7000
\n" ); document.write( "6000*0.03+1000*0.07 = 250
\n" ); document.write( "Both conditions are verified.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Answer:
\n" ); document.write( "$6000 invested at 3%
\n" ); document.write( "$1000 invested at 7%
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