document.write( "Question 1199890: A total of $7000 is deposited into two simple interest accounts. In one account the annual simple interest rate is 3%, and in the second account the annual simple interest rate is 7%. The amount of interest earned for 1 year was $250. How much was invested in each account? \n" ); document.write( "
Algebra.Com's Answer #833867 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The simple interest formula is \n" ); document.write( "i = P*r*t \n" ); document.write( "where, \n" ); document.write( "i = interest \n" ); document.write( "P = deposit \n" ); document.write( "r = interest rate in decimal form \n" ); document.write( "t = number of years\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let \n" ); document.write( "x = amount deposited at 3% rate \n" ); document.write( "7000-x = amount deposited at 7% rate \n" ); document.write( "The two items add to $7000\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For the 3% account \n" ); document.write( "i = P*r*t \n" ); document.write( "i = x*0.03*1 \n" ); document.write( "i = 0.03x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For the 7% account \n" ); document.write( "i = P*r*t \n" ); document.write( "i = (7000-x)*0.07*1 \n" ); document.write( "i = 490-0.07x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Total interest = 0.03x+(490-0.07x) \n" ); document.write( "Total interest = -0.04x+490\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Set that equal to $250 and solve for x. \n" ); document.write( "Total interest = 250 \n" ); document.write( "-0.04x+490 = 250 \n" ); document.write( "-0.04x = 250-490 \n" ); document.write( "-0.04x = -240 \n" ); document.write( "x = -240/(-0.04) \n" ); document.write( "x = 6000 \n" ); document.write( "$6000 was invested at 3% interest rate.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then use mental math to determine the remaining amount invested must be $1000\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Or you can say: 7000-x = 7000-6000 = 1000\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "6000+1000 = 7000 \n" ); document.write( "6000*0.03+1000*0.07 = 250 \n" ); document.write( "Both conditions are verified.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: \n" ); document.write( "$6000 invested at 3% \n" ); document.write( "$1000 invested at 7% \n" ); document.write( " \n" ); document.write( " |