document.write( "Question 1199846: ABCD and DEFG are congruent squares. Find the measurement of angle ACF
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Algebra.Com's Answer #833834 by ikleyn(52798) $\"\"$ $\"About$

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document.write( "(a)  Triangle CDE is equilateral triangle \r\n" );
document.write( "     (since it is isosceles CD = ED and the angle between \r\n" );
document.write( "      these congruent sides is 60°).\r\n" );
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document.write( "      Therefore, all its interior angles are 60° each.\r\n" );
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document.write( "(b)  angle ACE is 45° + 60° = 105°.\r\n" );
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document.write( "     angle CEF is 60° + 90° = 150°.\r\n" );
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document.write( "(c)  Triangle CEF is isosceles, since  CE = EF.\r\n" );
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document.write( "     Therefore, angle FCE =  =  = 15°.\r\n" );
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document.write( "(d)  < ACF = < ACE - < FCE = 105° - 15° = 90°.\r\n" );
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document.write( "ANSWER.  Angle ACF is 90° (right angle).\r\n" );
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