document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=114605>Question 114605</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For this question i have to sketch and label a graph, show all calculations and leave them in either factored or vertex form. I also have to keep 4 decimal places through my solutions and then round final answer to one decimal place. The question is :\r<BR>\n" );
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document.write( "A farmer has $2400 to spend on two rectangular pastures as shown to the right. (the diagram is of 2 identical shaped rectangles attatched by one of the length sides). The local contractor will build the fence at a cost of $6.25/m. What is the largest total area the farmer can have fenced for that price??<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #83382 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=83382\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A farmer has $2400 to spend on two rectangular pastures as shown to the right.<BR>\n" );
document.write( " (the diagram is of 2 identical shaped rectangles attached by one of the length<BR>\n" );
document.write( " sides). The local contractor will build the fence at a cost of $6.25/m.<BR>\n" );
document.write( " What is the largest total area the farmer can have fenced for that price??<BR>\n" );
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document.write( "Find out how many meters of fence he can get for $2400:<BR>\n" );
document.write( "2400/6.25 =  384 meters of fence<BR>\n" );
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document.write( "Using a modified perimeter equation:<BR>\n" );
document.write( "2L + 3W = 384<BR>\n" );
document.write( "2L = 384 - 3W<BR>\n" );
document.write( "L = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=384%2F2 ALIGN=MIDDLE  ALT=\"384%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > - <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F2 ALIGN=MIDDLE  ALT=\"3%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >W<BR>\n" );
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document.write( "L = (192 - 1.5W)<BR>\n" );
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document.write( "Area = L * W<BR>\n" );
document.write( "Substitute (192-1.5W) for L<BR>\n" );
document.write( "A = W(192-1.5W) <BR>\n" );
document.write( "A = -1.5w^2 + 192w<BR>\n" );
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document.write( "Max area occurs at the axis of symmetry. Find the axis of symmetry: (x=-b/2a)<BR>\n" );
document.write( "w = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-192%29%2F%282%2A-1.5%29 ALIGN=MIDDLE  ALT=\"%28-192%29%2F%282%2A-1.5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "W = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-192%29%2F%28-3%29 ALIGN=MIDDLE  ALT=\"%28-192%29%2F%28-3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "W = +64 meters<BR>\n" );
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document.write( "Find L:<BR>\n" );
document.write( "L = 192 - 1.5(64)<BR>\n" );
document.write( "L = 192 - 96<BR>\n" );
document.write( "L = 96 meters<BR>\n" );
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document.write( "Max area: 96 * 64 = 6144 sq meters for $2400<BR>\n" );
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document.write( "You can confirm this by finding the vertex: Substitute 64 for w:<BR>\n" );
document.write( "A = -1.5(64^2) + 192(64)<BR>\n" );
document.write( "A = -6144 + 12288<BR>\n" );
document.write( "A = +6144<BR>\n" );
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