document.write( "Question 1199803: joan is three times as old as her son richard. ten years from now, joan will be two times as old as richard. how old are they now? \n" ); document.write( "

Algebra.Com's Answer #833766 by ikleyn(52778) $\"\"$ $\"About$

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document.write( " x = the son current age;\r\n" );
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document.write( "3x = Joan current age.\r\n" );
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document.write( "In 10 years from now\r\n" );
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document.write( "    3x + 10 = 2*(x+10)\r\n" );
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document.write( "    3x + 10 = 2x + 20\r\n" );
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document.write( "    3x - 2x = 20 - 10\r\n" );
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document.write( "       x    =    10.\r\n" );
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document.write( "ANSWER.  The son is 10 years old.  Joan is 3*10 = 30 years old.\r\n" );
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