document.write( "Question 1199772: Let X be a binomial random variable with n = 75 and p = 0.6\r
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Algebra.Com's Answer #833760 by ikleyn(52835) $\"\"$ $\"About$

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\n" ); document.write( "Let X be a binomial random variable with n = 75 and p = 0.6
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\n" ); document.write( "c) What is the probability of P(x≥52), without continuity correction and with continuity correction.
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document.write( "(a)  μ is the mean       μ = n*p = 0.6*0.75 = 45.\r\n" );
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document.write( "(b)  σ2 is the variance  σ2 = n*p*(1-p)= 75*0.6*(1-0.6) = 18.\r\n" );
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document.write( "(c)  P(x>=52) without continuity correction = normalcdf(52, 9999, μ, σ) = normalcdf(52, 9999, 45, 4.24264).\r\n" );
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document.write( "     Use your calculator.  Here 4.24264 = .\r\n" );
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document.write( "     P(x>=52) with continuity correction = normalcdf(51.5, 9999, μ, σ) = normalcdf(51.5, 9999, 45, 4.24264).\r\n" );
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document.write( "     Use your calculator, again.\r\n" );
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