document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1199766>Question 1199766</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One speed skater starts across a frozen lakebat an average speed of 8 m / s. Ten minutes later, a second skater start from the same points and skate the same direction at speed of 9m/s. How many seconds after the 2 and skater will overtake the first skater? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #833736 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13209)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=833736\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "In 10 minutes at 8 m/s, the first skater travels (10)(60)(8) = 4800 m.<br><BR>\n" );
document.write( "The rate at which the second skater catches up to the first is the difference in their speeds, which is 1 m/s.<br><BR>\n" );
document.write( "To make up the 4800 m at the rate of 1 m/s takes 4800/1 = 4800 seconds.<br><BR>\n" );
document.write( "ANSWER: 4800 seconds<br><BR>\n" );
document.write( "(notes....)<BR>\n" );
document.write( "(1) That's a very long frozen lake<BR>\n" );
document.write( "(2) Speed skaters don't maintain speeds like that for those amounts of time<br><BR>\n" );
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