document.write( "Question 1199752: How many mL's of a 10% alcohol solution and how many mL's of a 20% solution must be mixed to obtain 30 mL's of a 16% solution? \n" ); document.write( "
Algebra.Com's Answer #833727 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "If a formal mathematical solution is required, then something like the setup shown by the other tutor is standard. \n" ); document.write( "If formal math is not required, and if the speed of finding the answer is important, here is a quick and easy way to solve any 2-part mixture problem like this: \n" ); document.write( "16% is 6/10 = 3/5 of the way from 10% to 20%; \n" ); document.write( "therefore 3/5 of the mixture should be the ingredient with the higher percentage. \n" ); document.write( "ANSWER: 3/5 of 30mL, or 18mL, of the 20% solution; the other 12mL of the 10% solution \n" ); document.write( "CHECK: \n" ); document.write( ".20(12)+.30(18) = 3.6+5.4 = 9.0 \n" ); document.write( ".30(30) = 9.0 \n" ); document.write( " \n" ); document.write( " |