document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1199755>Question 1199755</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two identical spheres of diameter 6 cm have the same total volume as<BR>\n" );
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document.write( "a) one sphere with diameter 12 cm<BR>\n" );
document.write( "b) four identical spheres each with diameter 3 cm <BR>\n" );
document.write( "c) eight identical spheres each with diameter 4 cm <BR>\n" );
document.write( "d) sixteen identical spheres each with diameter 3 cm<BR>\n" );
document.write( "e) thirty-two identical spheres each with diameter 2 cm </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #833718 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=833718\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The volume is proportional to the cube of the diameter.  So for the total volume to stay the same, you can...<BR>\n" );
document.write( "(1) double (multiply by 2) the diameter and divide the number of spheres by 2^3=8<BR>\n" );
document.write( "(2) divide the diameter by 2 and multiply the number of spheres by 2^3=8<BR>\n" );
document.write( "or, in general,<BR>\n" );
document.write( "(3) divide the diameter by a factor x and multiply the number of spheres by x^3<br><BR>\n" );
document.write( "Option (2) above gives you a diameter of 6/2 = 3 cm and 2(2^3) = 2(8) = 16 spheres, which is answer choice d.<br><BR>\n" );
document.write( "ANSWER: d) 16 spheres each with diameter 3cm<br><BR>\n" );
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