document.write( "Question 1199691: Solve 2x-1 < (x+7)/(x+1) algebraically \n" ); document.write( "

Algebra.Com's Answer #833716 by MathTherapy(10552) $\"\"$ $\"About$

You can put this solution on YOUR website!

\r\n" );
document.write( "Solve   2x-1 < (x+7)/(x+1)  algebraically\r\n" );
document.write( "\r\n" );
document.write( "Contrary to what the other person states, you CAN multiply by the LCD, x + 1\r\n" );
document.write( "\r\n" );
document.write( "Since denominator is x + 1, it follows that: \r\n" );
document.write( "          \r\n" );
document.write( "(2x - 1)(x + 1) < x + 7 ----- Multiplying by LCD, x + 1\r\n" );
document.write( "    \r\n" );
document.write( "(x - 2)(x + 2) < 0\r\n" );
document.write( "x - 2 < 0         OR      x + 2 < 0\r\n" );
document.write( "x < 2             OR      x < - 2\r\n" );
document.write( "Since , - 2, - 1, and 2 will be the CRITICAL points.\r\n" );
document.write( "\r\n" );
document.write( "With the 3 CRITICAL POINTS above, we get the 4 TEST INTERVALS: \r\n" );
document.write( "  x < - 2___x = - 3    - 2 < x < - 1___x = - 1.5  -1 < x < 2__x = 0    x > 2___x = 3 \r\n" );
document.write( "       \r\n" );
document.write( "\r\n" );
document.write( "Solution sets: x < - 2, and - 1 < x < 2 since these are the ONLY TRUE STATEMENTS.\r\n" );
document.write( "In INTERVAL NOTATION, we get: ()()

\n" ); document.write( "

\n" );