document.write( "Question 1199746: Mike was given some problem sums to complete. He completed 5/9 of the questions on Monday, 2 questions on Tuesday and 15 fewer questions than 4/11, of the remaining questions on Wednesday. Given that he had 57 questions left to complete on Thursday, find the number of questions Mike was given at first. \n" ); document.write( "

Algebra.Com's Answer #833712 by greenestamps(13203) $\"\"$ $\"About$

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\n" ); document.write( "Let x be the original number of questions.

\r\n" );
document.write( "                solved               left to solve\r\n" );
document.write( "    -------------------------------------------\r\n" );
document.write( "     Monday     (5/9)x               (4/9)x\r\n" );
document.write( "     Tuesday      2                  (4/9)x-2\r\n" );
document.write( "     Wednesday  (4/11)((4/9)x-2)-15   57\r\n" );
document.write( "     Thursday    57                    0

\n" ); document.write( "All the questions were finished by Thursday:

\n" ); document.write( " $\"%28%285%2F9%29x%29%2B%282%29%2B%28%284%2F11%29%28%284%2F9%29x-2%29-15%29%2B%2857%29=x\"$
\n" ); document.write( " $\"%28%285%2F9%29x%29%2B%282%29%2B%28%2816%2F99%29x-8%2F11-15%29%2B%2857%29=x\"$
\n" ); document.write( " $\"%2855%2F99%29x%2B2%2B%2816%2F99%29x-8%2F11-15%2B57=%2899%2F99%29\"$
\n" ); document.write( " $\"44-8%2F11+=+%2828%2F99%29x\"$
\n" ); document.write( " $\"476%2F11=%2828%2F99%29x\"$
\n" ); document.write( " $\"x=%2899%2F28%29%28476%2F11%29=%28476%2F28%29%2899%2F11%29=17%2A9=153\"$

\n" ); document.write( "ANSWER: 153

\n" ); document.write( "CHECK:
\n" ); document.write( "start: 153
\n" ); document.write( "Monday: finished (5/9)153 = 85; remaining 153-85 = 68
\n" ); document.write( "Tuesday: finished 2; remaining 68-2 = 66
\n" ); document.write( "Wednesday: finished (4/11)(66)-15 = 24-15 = 9; remaining 66-9 = 57

\n" ); document.write( " \n" ); document.write( "

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