document.write( "Question 1199742: The circle with center O is inscribed in kite ABCD. Find the length of the radius of the circle, in cm.\r
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\n" ); document.write( "\n" ); document.write( "A) 9 \"+3%2F5+\"
\n" ); document.write( "B) 8 \"+5%2F11+\"
\n" ); document.write( "C) 11 \"+1%2F3+\"
\n" ); document.write( "D) 10 \"+2%2F7+\"
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Algebra.Com's Answer #833707 by ikleyn(52799)\"\" \"About 
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\n" ); document.write( "The circle with center O is inscribed in kite ABCD. Find the length of the radius of the circle, in cm.
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document.write( "The area of the right-angled triangle ABC is half the product of its legs  \"%281%2F2%29%2A24%2A18\" cm^2.\r\n" );
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document.write( "The area of the right-angled triangle ADC is the same \"%281%2F2%29%2A24%2A18\" cm^2.\r\n" );
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document.write( "So, the area of the kit is simply  24*18  cm^2.\r\n" );
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document.write( "    For any convex polygon circumscribed around a circle, \r\n" );
document.write( "    its area is half the product the radius of the circle \r\n" );
document.write( "    by the perimeter of the polygon\r\n" );
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document.write( "        area of the polygon = \"%281%2F2%29%2Ar%2AP\".\r\n" );
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document.write( "In our case, the perimeter of the kite is 2*(24+18) = 2*42 = 84 cm.\r\n" );
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document.write( "So we have\r\n" );
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document.write( "    area of the kite = 24*18 = \"%281%2F2%29%2Ar%2A84\" = 42r,\r\n" );
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document.write( "which gives  r = \"%2824%2A18%29%2F42\" = \"%284%2A18%29%2F7\" = \"72%2F7\" = 10 \"2%2F7\" cm.    ANSWER\r\n" );
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