document.write( "Question 1199716: The length and width of a rectangular solid are decreased by 30%, and the height is doubled. The ratio of the volume of the new solid to the volume of the original solid is __ \n" ); document.write( "
Algebra.Com's Answer #833680 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "L = length
\n" ); document.write( "W = width
\n" ); document.write( "H = height
\n" ); document.write( "volume = LWH\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The length and width are decreased by 30%
\n" ); document.write( "They keep the remaining 70%
\n" ); document.write( "0.7L and 0.7W represent the new length and width respectively.
\n" ); document.write( "The height is doubled to go from H to 2H\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "new volume = (new length)*(new width)*(new height)
\n" ); document.write( "new volume = (0.7L)*(0.7W)*(2H)
\n" ); document.write( "new volume = (0.7*0.7*2)*(LWH)
\n" ); document.write( "new volume = (0.7*0.7*2)*(old volume)
\n" ); document.write( "new volume = 0.98*(old volume)
\n" ); document.write( "(new volume)/(old volume) = 0.98\r
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\n" ); document.write( "\n" ); document.write( "Interpretation:
\n" ); document.write( "The new volume is 98% of the old volume
\n" ); document.write( "In other words, there is a 2% loss in volume.
\n" ); document.write( "It would be like going from 100 cubic inches to 98 cubic inches.
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