document.write( "Question 1199682: ALGEBRAIC FRACTIONS
\n" ); document.write( "6-a-a^2 division a^2-4 is = -3+a division a+2
\n" ); document.write( " This is how I worked it out: \r
\n" ); document.write( "\n" ); document.write( "numerator :(-3-a)(-2+a) factored\r
\n" ); document.write( "\n" ); document.write( "denominator : (a-2)(a+2) factored \r
\n" ); document.write( "\n" ); document.write( "(-3-a)(-2+a) division (a-2)(a+2)
\n" ); document.write( "(-2+a) is the same as (a-2) which would cancel with (a+2)
\n" ); document.write( "so what is left is :
\n" ); document.write( "(-3-a) division (a-2) , as you can see the terms are the same as the answer except the signs in front of them . Why are the signs different ? Does it have to do with when I cancelled (a-2) with (a+2) ?\r
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Algebra.Com's Answer #833637 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
6-a-a^2 division a^2-4 is = -3+a division a+2
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\n" ); document.write( "(6-a-a^2)/(a^2-4) = (a-3)/(a+2)
\n" ); document.write( "\"-%28a%2B3%29%2A%28a-2%29%2F%28%28a-2%29%2A%28a%2B2%29%29+=+%28a-3%29%2F%28a%2B2%29\"
\n" ); document.write( "\"-%28a%2B3%29%2F%28a%2B2%29+=+%28a-3%29%2F%28a%2B2%29\"
\n" ); document.write( "-a-3 = a-3
\n" ); document.write( "a = 0
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