document.write( "Question 1199679: A train ticket in a certain city is $1.50. People who use the train also have the option of purchasing a frequent rider pass for $17.25 each month. With the pass, each ticket costs only $0.75. Determine the number of times in a month the train must be used so that the total monthly cost without the pass is the same as the total monthly cost with the pass. \n" ); document.write( "
Algebra.Com's Answer #833635 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
x, number of tickets in a month\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "without the pass: \"1.5x\"\r
\n" ); document.write( "\n" ); document.write( "with the pass: \"0.75x%2B17.25\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Look for the solution of \"1.5x=0.75x%2B17.25\".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "--\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"0.75x=17.25\"\r
\n" ); document.write( "\n" ); document.write( "\"x=17.25%2F0.75\"\r
\n" ); document.write( "\n" ); document.write( "\"x=23\"
\n" ); document.write( "
\n" );