document.write( "Question 1199667: Jon buys a bag of cookies that contains 7 chocolate chip cookies, 6 peanut butter cookies, 8 sugar cookies and 5 oatmeal cookies. What is the probability that Jon randomly selects a chocolate chip cookie from the bag, eats it, then randomly selects a sugar cookie?\r
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document.write( "Probability =
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document.write( " (Round to 4 decimal places) \n" );
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Algebra.Com's Answer #833634 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "A = event of selecting a chocolate chip cookie on the 1st selection \n" ); document.write( "P(A) = (number of chocolate chip)/(number total) \n" ); document.write( "P(A) = (7 chocolate chip)/(7+6+8+5 total) \n" ); document.write( "P(A) = (7 chocolate chip)/(26 total) \n" ); document.write( "P(A) = 7/26\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The fact that Jon eats the 1st cookie means no replacement is done. \n" ); document.write( "This will affect the probability of the 2nd cookie (hence the events aren't independent).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "B = event of selecting a sugar cookie on the 2nd selection\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(B given A) = probability B happens if event A happened \n" ); document.write( "P(B given A) = (number of sugar cookies)/(total number left) \n" ); document.write( "P(B given A) = (8 sugar cookies)/(26-1 left over) \n" ); document.write( "P(B given A) = (8 sugar cookies)/(25 left over) \n" ); document.write( "P(B given A) = 8/25 \n" ); document.write( "For more information, search out \"conditional probability\".\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Lastly, \n" ); document.write( "P(A and B) = P(A) * P(B given A) \n" ); document.write( "P(A and B) = (7/26)*(8/25) \n" ); document.write( "P(A and B) = 0.08615384615384 approximately \n" ); document.write( "P(A and B) = 0.0862 \n" ); document.write( "There's about an 8.62% chance of this happening.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 0.0862 \n" ); document.write( " \n" ); document.write( " |