document.write( "Question 1199664: In the diagram ∠TPQ = ∠SPR and TP ⊥ SR. Find the measure of ∠SRP
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Algebra.Com's Answer #833621 by Edwin McCravy(20059)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Extend TP to U\r\n" );
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document.write( "∠TPQ = ∠UPR because they are vertical angles.\r\n" );
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document.write( "∠TPQ = ∠SPR = ∠UPR\r\n" );
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document.write( "PR bisects ∠UPS\r\n" );
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document.write( "ΔSUP is a right triangle\r\n" );
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document.write( "∠UPS is complementary to ∠USP = 41o\r\n" );
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document.write( "∠UPS = 90o - 41o = 49o\r\n" );
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document.write( "∠RPS is half of ∠UPS, and half of 49o is 24.5o  \r\n" );
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document.write( "We now know two angles of ΔSRP, 24.5o and 41o,\r\n" );
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document.write( "So we add them and subtract from 180o.\r\n" );
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document.write( "∠SRP = 180o-(24.5o+41o) = 114.5o\r\n" );
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document.write( "Edwin
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