document.write( "Question 1199654: An investor invested a total of $800 in two mutual funds. One fund earned a 7% profit while the other earned a 2% profit. If the investor's total profit was $26, how much was invested in each mutual fund? \n" ); document.write( "
Algebra.Com's Answer #833619 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Here is an quick and easy informal method for solving any 2-part \"mixture\" problem like this. \n" ); document.write( "(1) All $800 invested at 2% would earn $16 interest; all at 7% would earn $56 interest. \n" ); document.write( "(2) The actual interest, $26, was 10/40 = 1/4 of the way from $16 to $56. ($16 to $56 is a difference of 40; $16 to $26 is a difference of 10; 10/40 = 1/4.) \n" ); document.write( "(3) That means 1/4 of the total was invested at the higher rate. \n" ); document.write( "1/4 of $800 is $200; so \n" ); document.write( "ANSWERS: $200 was invested at 7% and the other $600 at 2%. \n" ); document.write( "CHECK: .07(200)+.02(600) = 14+12 = 26 \n" ); document.write( " \n" ); document.write( " |