document.write( "Question 1199654: An investor invested a total of ​$800 in two mutual funds. One fund earned a 7​% profit while the other earned a 2% profit. If the​ investor's total profit was ​$26​, how much was invested in each mutual​ fund? \n" ); document.write( "
Algebra.Com's Answer #833619 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Here is an quick and easy informal method for solving any 2-part \"mixture\" problem like this.

\n" ); document.write( "(1) All $800 invested at 2% would earn $16 interest; all at 7% would earn $56 interest.
\n" ); document.write( "(2) The actual interest, $26, was 10/40 = 1/4 of the way from $16 to $56. ($16 to $56 is a difference of 40; $16 to $26 is a difference of 10; 10/40 = 1/4.)
\n" ); document.write( "(3) That means 1/4 of the total was invested at the higher rate.

\n" ); document.write( "1/4 of $800 is $200; so

\n" ); document.write( "ANSWERS: $200 was invested at 7% and the other $600 at 2%.

\n" ); document.write( "CHECK: .07(200)+.02(600) = 14+12 = 26

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